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What would be the amount of heat released when an aqueous solution containing
0.3 mole of $H N O_{3}$ is mixed with 0.3 mole of $O H^{-} (Δ H_{n e u t r a l i s a t i o n} = - 57.1 K J)$

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28.5 KJ

$17.1 K J$

4100 Cal

4.1 KCal

answer is C.

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Detailed Solution

$H^{+} + O H^{-} \to H_{2} O Δ H = - 57.1 K J / m o l$
0.3 mole $O H^{-}$ will react with 0.3 mole $H^{+}$
Heat evolved $= 0.3 \times 57.1 K J$ $= 17.13 K J$

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