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Q.

What would be the minimum uncertainly in de-Broglie wavelength of a moving electron accelerated by potential difference of 6 volt and whose uncertainty in position is $\frac{7}{22}$ nm?

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a

$6 A^{ο}$

b

$0.3125 A^{ο}$

c

$0.625 A^{ο}$

d

$6.25 A^{ο}$

answer is C.

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Detailed Solution

$Δ x . Δ p = \frac{h}{4 π} (∵ Δ p = \frac{h}{λ^{2}} . Δ λ)$

$λ = \sqrt{\frac{150}{v (v o l t s)}} {}^{0}A, λ = \frac{h}{p}$

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