What would be the molality of $20\%$ ($mass/mass$) aqueous solution of $KI$(molar mass of $Kl =166gmo{l}^{-1}$)

$\frac{w}{w}\mathrm{\%}=20$

$100gm$ solution has $20gm KI$

$80gm$solution has $20gm KI$

$m=\frac{\frac{20}{166}}{\frac{80}{1000}}=\frac{20\times 1000}{166\times 80}=1.506\cong 1.51\mathrm{mol}/\mathrm{kg}$.