What would be the SI unit for the quantity pV2T2n?

pV2T2n=Nm-2)·(m)32( K)2mol=Nm4 K2 mol-1

What would be the SI unit for the quantity pV2T2n?

pV2T2n=Nm-2)·(m)32( K)2mol=Nm4 K2 mol-1

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What would be the SI unit for the quantity $\frac{{pV}^{2} T^{2}}{n}$ ?

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${Nm}^{4} K^{2} {mol}^{- 1}$

${Nm}^{2} K {mol}^{- 2}$

${Nm}^{3} K^{3} {mol}^{- 1}$

${Nm}^{3} K^{2} {mol}^{- 2}$

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Detailed Solution

$\frac{{pV}^{2} T^{2}}{n} = \frac{({Nm}^{- 2)} \cdot {\{(m)^{3}\}}^{2} (K)^{2}}{mol} = {Nm}^{4} K^{2} {mol}^{- 1}$

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What would be the SI unit for the quantity pV2T2n?

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What would be the SI unit for the quantity $\frac{{pV}^{2} T^{2}}{n}$ ?