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What would be the wavelength of a sound wave in iron (V = 4950 m/sec) if its wavelength was 1.4 m in air in which its speed was 330 m/sec.

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0.29

21 m

17 m

18 m

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{v_{1}}{v_{2}} = \frac{λ_{1}}{λ_{2}} \Rightarrow λ_{2} = \frac{v_{2}}{v_{1}} λ_{1} \\ \Rightarrow λ_{2} = \frac{4950}{330} \times 1.4 = 21 m \end{array}$

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