What is the correct option regarding the dipole moment of trans-$\text{CHF}=\text{CHF}$?

The trans $\text{CHF}=\text{CHF}$ structure and direction of dipole moments are:

So, from this structure, it is shown that the direction of dipole moments vectors of two trans carbon fluorine bonds are completely the same but in opposite to each other. So, they cancel out, as a result, the net dipole moment is zero that is $\mu =0$ .

Therefore, the correct option is $1$.