When ethanol reacts with sodium metal, it forms two products. These products are

Ethyl alcohol reacts with sodium metal to form sodium ethoxide and hydrogen gas in the following way.

${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}\text{OH(aq)}+\text{Na(s)}\to {\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}\text{ONa(aq)}+\frac{1}{2}{\text{H}}_{\text{2}}\left(g\right)\uparrow$ .