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When 0.005 A current flows through a moving coil galvanometer, it gives full scale deflection. It is converted into a voltmeter to read 5 Volt, using an external resistance of 975 Ω. The resistance of galvanometer in ohms is

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answer is D.

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Detailed Solution

$\begin{array}{l} i_{g} = 0.005 A, V = 5 V; G = ? R = 975 Ω \\ V = i_{g} [G + R]; G = 1000 - 975 = 25 Ω \end{array}$

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