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When 0.1 mole of an acid is added to 2 lit of a buffer solution, the $P^{H}$ of the buffer decreases by 0.5. The buffer capacity of the solution is

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0.6

0.4

0.2

0.1

answer is D.

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Detailed Solution

$ϕ = \frac{n}{Δ P^{H}}$

$= \frac{\frac{0.1}{2}}{0.5}$

$= \frac{1}{5 \times 2}$

$= \frac{1}{10}$

$= 0.1$

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