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Q.

When 1.04g of BaCl₂ is present in $10^{5} g$ of solution the concentration of solution is

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a

0.104 ppm

b

10.4 ppm

c

0.0104 ppm

d

104 ppm

answer is B.

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Detailed Solution

$= \frac{1.04 \times 10^{6}}{10^{5}}$ =10.4 ppm

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