When 1-alkyne is treated with Na + Liq. ${\mathrm{NH}}_3$ and product is reacted with methyl chloride, the end product of the reaction will be

Higher alkyne having one carbon more than 1-alkyne

Lower alkyne having two carbons less than 1-alkyne

Lower alkyne having one carbons less than 1-alkyne

Higher alkyne having two carbons more than 1-alkyne