When 1 litre of $1 M HCl$ is mixed with 1 litre of $1 M NaOH$ , the rise in temperature was found to be $T_{1}$ . In another experiment 1 litre of $0.5 M NaOH$ is mixed with 1 lit. of $0.5 M$ $HCl$ . The rise in temperature was found to be $T_{2}$ . Then

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$T_{1} = T_{2}$

$T_{2} = 2 T_{1}$

$T_{1} = 2 T_{2}$

$T_{1} < T_{2}$

answer is C.

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Detailed Solution

Heat liberated ∝moles of salt formed ∝ temperature rise …………(i)

Let temperature in case $(1), T_{1}$ and in case $(2), T_{2}$ .

$HCl + NaOH \to NaCl + H_{2} O$

Here in case 1,1 mole product is formed from 1 mole of each given reactant.

In case $2, 0.5$ mole product is produced from $0.5$ mole of each given reactant.

Hence using (i), $T_{1} = 2 T_{2}$

Hence option C is the correct answer.

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