When 1 m, 1 kg and 1 min are taken as the fundamental units, the magnitude of the force is 36 units. What will be the value of this force in CGS system?

As, dimensional formula of force = [MLT^-2] 
n₁ = 36, M₁ = 1kg, L₁ = 1m, T₁ = 1min=60s
n₂ = ?, M₂ = 1g, L₂ = 1cm, T₂ = 1s
So, conversion of 36 units into CGS system, 
$$\begin{gathered} \mathrm{i}.\mathrm{e}., {\mathrm{n}}_2={\mathrm{n}}_1{\left[\frac{{\mathrm{M}}_1}{{\mathrm{M}}_2}\right]}^{\mathrm{a}}{\left[\frac{{\mathrm{L}}_1}{{\mathrm{L}}_2}\right]}^{\mathrm{b}}{\left[\frac{{\mathrm{T}}_1}{{\mathrm{T}}_2}\right]}^{\mathrm{c}} \\ \Rightarrow {\mathrm{n}}_2={\mathrm{n}}_1{\left[\frac{1 \mathrm{kg}}{1\mathrm{g}}\right]}^1{\left[\frac{1\mathrm{m}}{1\mathrm{cm}}\right]}^1{\left[\frac{1\min }{1\mathrm{s}}\right]}^{-2} \\ =36\left[\frac{1000\mathrm{g}}{1\mathrm{g}}\right]{\left[\frac{100\mathrm{cm}}{1\mathrm{cm}}\right]}^1{\left[\frac{60\mathrm{s}}{1\mathrm{s}}\right]}^{-2}={10}^3\mathrm{dyne} \end{gathered}$$