When 1 mole of CrCl3. 6H2O is treated with excess of AgNO3, 3 moles of AgCl are obtained. The formula of the complex is

[Cr(H2O)6 ]Cl3CrCl3.6H2O or CrH2O6Cl3→CrH2O63++3Cl−3Cl−+3AgNO3→3AgCl↓+3NO3−

When 1 mole of CrCl3. 6H2O is treated with excess of AgNO3, 3 moles of AgCl are obtained. The formula of the complex is

[Cr(H2O)6 ]Cl3CrCl3.6H2O or CrH2O6Cl3→CrH2O63++3Cl−3Cl−+3AgNO3→3AgCl↓+3NO3−

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When 1 mole of CrCl₃. 6H₂O is treated with excess of AgNO₃, 3 moles of AgCl are obtained. The formula of the complex is

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[Cr (H₂O)₆]Cl₃

[CrCl₂(H₂ O)₅] Cl.H₂O

[CrCl₃(H₂O)₃].3H₂O

[CrCl₂ (H₂O)₄] Cl.2H₂O

answer is D.

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[Cr(H₂O)₆ ]Cl₃

$\begin{array}{l} {CrCl}_{3} . 6 H_{2} O or [Cr {(H_{2} O)}_{6}] {Cl}_{3} \to {[Cr {(H_{2} O)}_{6}]}^{3 +} + 3 {Cl}^{-} \\ 3 {Cl}^{-} + 3 {AgNO}_{3} \to 3 AgCl ↓ + 3 {NO}_{3}^{-} \end{array}$

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When 1 mole of CrCl3. 6H2O is treated with excess of AgNO3, 3 moles of AgCl are obtained. The formula of the complex is

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When 1 mole of CrCl₃. 6H₂O is treated with excess of AgNO₃, 3 moles of AgCl are obtained. The formula of the complex is