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Q.

When 100 ml of N/10 NaOH are added to 50 ml of N/5 HCl, the pH of the resulting solution is

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a

7

b

Zero

c

less than 7

d

greater than 7

answer is A.

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Detailed Solution

$NaVa = N_{6} V_{6}$

$\frac{N}{10} \times 100 = \frac{N}{5} \times 50$

10N = 10N

It is neutral

$[H^{+}] = [O H^{-}] = 10^{- 7}$

$∴ PH = 7$

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When 100 ml of N/10 NaOH are added to 50 ml of N/5 HCl, the pH of the resulting solution is