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Q.

When 100 V DC is applied across a solenoid, a current of 1 A flows in it. When 100 V AC is applied across the same solenoid the current drops to 0.5 A. If the frequency of the AC source is 50 Hz, the impedance and inductance of the solenoid are 

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a

100Ω and 0.86H

b

200Ω and 1.0H

c

1100Ω and 0.93H

d

200Ω and 0.55H

answer is A.

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Detailed Solution

For DC : -  i=VR

⇒1=100R⇒R=100Ω
For DC : -  i=VZ

⇒0.5=100Z⇒Z=200Ω
 
Z=R2+xL2

⇒(200)2=(100)2+4π2(50)2L2⇒L=0.55H

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