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When $10^{14}$ electrons are removed from a neutral metal sphere, the charge on it becomes

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$16 μ C$

$- 16 μ C$

$32 μ C$

$- 32 μ C$

answer is A.

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Detailed Solution

$q = + n e$

$q = + (1.6 \times 10^{- 19}) (10^{14}) = + 1.6 \times 10^{- 5} C = 16 μ C$

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