When 12.2 g of benzoic acid is dissolved in 100 g of water, the freezing point solution was found to be – 0.93^oC (Kf (H2O) = 1.86 K kg mol–1). The number (n) of benzoic acid molecules associated (assuming 100% association) is ____

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answer is 2.

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Detailed Solution

$Δ T_{f} = i \times k_{f} \times m$
$0 - (- 0.93) = i \times 1.86 \times \frac{12.2}{122 \times 100} \times 1000$
$i = \frac{0.93}{1.86} = 0.5$
$i = 1 + (\frac{1}{n} - 1) α$
$\frac{1}{2} = 1 + (\frac{1}{n} - 1) \times 1$

Hence, the required value of n is 2.

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