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Q.

When 159.5g of $C u S O_{4}$ solution is reacted with KI, then the liberated iodine required 100 ml of 1 M $N a_{2} S_{2} O_{3}$ for complete reaction, then what is the percentage purity of Cu in $C u S O_{4}$ solution

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a

20%

b

10%

c

5%

d

40%

answer is A.

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Detailed Solution

No. of milli equivalents $C u^{+ 2} = 100$

$C u^{+ 2} = 100 \times 263.5 \times 10^{- 3} = 6.35 g$

159.5g of $C u S O_{4}$ should contain = 63.5g of copper

But only 6.35g Cu is present % $p u r i t y = \frac{6.35}{63.5} \times 100 = 10 %$

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When 159.5g of CuSO4 solution is reacted with KI, then the liberated iodine required 100 ml of 1 M Na2S2O3 for complete reaction, then what is the percentage purity of Cu in CuSO4 solution