When 2-butyne is treated with H₂ / Lindlar ' s catalyst, compound X is produced as the major product and when treated with Na / liqNH₃ it produces Y as the major product. Which of the following statements is correct?

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X will have lower dipole moment and lower boiling point than Y

Y will have higher dipole moment and lower boiling point than X

X will have higher dipole moment and higher boiling point than Y

Y will have higher dipole moment and higher boiling point than X

answer is D.

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Detailed Solution

CH3–C≡C–CH3 --(H2 / Lindlar's catalyst)--> cis-CH3–CH=CH–CH3

CH3–C≡C–CH3 --(Na / liq. NH3)--> trans-CH3–CH=CH–CH3

This shows the partial hydrogenation of 2-butyne:

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