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When 2-butyne reacts with sodamide in an inert solvent in the presence of dilute HCl, the product formed is :

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1-Butyne

n-Butane

1-Propyne

2-Butene

answer is C.

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Detailed Solution

When 2-butyne is heated with ${NaNH}_{2}$ in an inert solvent, the sodium derivative of but-1-yne which is converted into but-1-yne by the action of dil. HCl.

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