When 2 liters of mixture of CO and $C{O}_2$ passed over red hot coke 3.2 liters of the CO is obtained what volume of  $C{O}_2$ present in the original mixture

Reaction used is:

${\mathrm{CO}}_2+\mathrm{C}\to 2\mathrm{CO}$

1 mole of carbon dioxide and one mole of carbon forms 2 moles of CO.

If x is the moles of CO₂ reacted and 2x is the moles of CO produced.

 $Vco+Vc{o}_2$
$(2-X)\mathcal{l}X\mathcal{l}$
$\begin{array}{l}C{O}_2+C\stackrel{\Delta }{\to }2CO\\ \text{X }\mathcal{l}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}2 X }\mathcal{l}\end{array}$
V total  $CO=(2-x)+2x=2+x=3.2\text{\hspace{0.17em}liters}$
$VC{O}_2=x=1.2\text{\hspace{0.17em}liters}$