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When 20 ml of 2.5M H₂O₂ aqueous soultion is decomposed the S.T.P. volume of oxygen obtained is

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56 ml

560 ml

11.2 ml

2.24 vol

answer is B.

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Detailed Solution

$large {M_{{H_2}{O_2}}}; = ;2.5$

$large M; = ;n times frac{{1000}}{{V(in;ml)}}$

$large eta = ;frac{{M times v[in;ml]}}{{1000}}$

$large eta = ;frac{{2.5 times 20}}{{1000}}$

$large eta ; = ;0.05$

No.of moles of H₂O₂ (η)=0.05moles

large mathop {2{H_2}{O_2}}limits_{2;moles} {text{ }} to {text{ }}2{H_2}O + mathop {{O_2}}limits_{1;moles}

large \2;moles;of;{H_2}{O_2};solution;xrightarrow{{;;Pr oduces}};1 times 22400;ml = ;22.4lit;{O_2}

0.05 moles of H₂O₂ solution → ?? ml of O₂

$\frac{0.05 \times 22400}{2} = \frac{5 \times 224}{2}$

= 5 x 112
=560 ml

2ml of 2.5 H₂O₂ aqueous solution is on decomosition at STP produces 560 ml of O₂.

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