When 200 ml 0.2M NaCl and 200 ml 0.4M BaCl₂ and 100 ml 0.2 M KCl are mixed. Match the column-I (the ion) with column-II (molarity)
Column-I Column-II
A) molarity of Na⁺ ion P) 0.04 M
B) molarity of Ba⁺² ion Q) 0.08 M
C) molarity of Cl^– ion R) 0.16 M
D) molarity of K⁺ ion S) 0.44 M

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A-P ;B-Q ;C-R ; D-S

A-Q ;B-P ;C-R ; D-S

A-S ;B-Q ;C-R ; D-P

A-Q ; B-R ; C-S ; D-P

answer is A.

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Detailed Solution

$\begin{array}{l} A) [{Na}^{+}] = \frac{200 \times 0.2}{200 + 200 + 100} = 0.08 M \\ B) [{Ba}^{+ 2}] = \frac{200 \times 0.4}{500} = 0.16 M \\ C) [{Cl}^{-}] = \frac{200 \times 0.2 + 200 \times 0.4 \times 2 + 100 \times 0.2}{500} \\ = 0.44 M \\ D) [K^{+}] = \frac{100 \times 0.2}{500} = 0.04 M \end{array}$

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