When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is ______g.

Amount of wood charcoal taken=0.6 g
Moles of acetic acid taken= $0.2\times 200\times {10}^{-3}$
Moles of acetic acid after adsorption = $=0.1\times 200\times {10}^{-3}$
Moles of acetic acid adsorbed (on 0.6  gram charcoal)
$\begin{array}{l}=[0.2\times 200]\times {10}^{-3}-(0.1\times 200){10}^{-3}\\ =40\times {10}^{-3}-20\times {10}^{-3}=20\times {10}^{-3}\end{array}$

Weight of CH₃COOH adsorbed (on 0.6  gram charcoal)

$\begin{array}{l}=\left(20\times {10}^{-3}\right)60\\ =1200\times {10}^{-3}\text{ gram }=1.2\text{ gram }\end{array}$

Mass of CH₃COOH adsorbed per gram= $\frac{1.2}{0.6}=2\mathrm{gram}$