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Q.

When 2.00mol each of H2(g) and I2(g) are reacted in a 1.00 L container at a certain temperature. 3.50mol of HI is present at equilibrium. Calculate the value of the equilibrium constant, Kc for the reaction:

H2+I2⇌2HI

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a

14

b

2.0×102

c

56

d

3.7

answer is D.

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Detailed Solution

The reaction can be given as,

H22−x+I22−x⇌2HI2x=3.50

For this the equilibrium constant,

KC=(3.5)2(0.25)2 KC=196

So, the value of the equilibrium constant, Kc for the reaction is 2.0×102.

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