When 3-methly-1-butene reacts with Hg(OAC)2/THF – H2O followed by reduction with NaBH4, a compound ‘X’ is formed. How many stereoisomers are possible for ‘X’?

Treatment of 3-methyl-1-butene with Hg(CH3COO)2−H2O, THF followed by reduction with NaBH4/OH− gives 3-methyl-2-butanol. So, two stereoisomers are possible since, there is one chiral centerin the product.

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

When 3-methly-1-butene reacts with Hg(OAC)₂/THF – H₂O followed by reduction with NaBH₄, a compound ‘X’ is formed. How many stereoisomers are possible for ‘X’?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 2.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Treatment of 3-methyl-1-butene with Hg(CH₃COO)₂−H₂O, THF followed by reduction with NaBH₄/OH⁻ gives 3-methyl-2-butanol. So, two stereoisomers are possible since, there is one chiral center

in the product. Question Image

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th