When 3-methly-1-butene reacts with Hg(OAC)₂/THF – H₂O followed by reduction with NaBH₄, a compound ‘X’ is formed. How many stereoisomers are possible for ‘X’?

Treatment of 3-methyl-1-butene with Hg(CH₃​COO)₂​−H₂​O, THF followed by reduction with NaBH₄​/OH⁻ gives 3-methyl-2-butanol. So, two stereoisomers are possible since, there is one chiral center

in the product.