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When 3 moles of A and 1 mole of B are mixed in 1 litre vessel the following reaction takes place $A (g) + B (g) ⇌ 2 C (g)$ . 1.5 moles of C are formed. The equilibrium constant for the reaction is:

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Correct option is D

For the equilibrium reaction;

$A (g) + B (g) ⇌ 2 C (g)$

$\underset{3}{A} + \underset{1}{B} ⇌ \underline{2 C}$

$\begin{array}{ccc} 3 - x & 1 - x & 2 x \\ 3 - \frac{1.5}{2} & 1 - \frac{1.5}{2} & = 1.5 \end{array}$

$K = \frac{(1.5)^{2}}{0.25 \times 2.25}$

$K = 4$ .

The equilibrium constant for the reaction is 4.

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When 3 moles of A and 1 mole of B are mixed in 1 litre vessel the following reaction takes place A(g)+B(g)⇌2C(g). 1.5 moles of C are formed. The equilibrium constant for the reaction is:

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When 3 moles of A and 1 mole of B are mixed in 1 litre vessel the following reaction takes place $A (g) + B (g) ⇌ 2 C (g)$ . 1.5 moles of C are formed. The equilibrium constant for the reaction is: