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Q.

When 3 moles of A and 1 mole of B are mixed in 1 litre vessel the following reaction takes place A(g)+B(g)⇌2C(g). 1.5 moles of C are formed. The equilibrium constant for the reaction is:

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a

0.25

b

0.50

c

0.12

d

4.0

answer is D.

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Detailed Solution

For the equilibrium reaction;

A(g)+B(g)⇌2C(g)

A3+B1⇌2C- 

3−x1−x2x3−1.521−1.52=1.5

K=(1.5)20.25×2.25

K=4.

The equilibrium constant for the reaction is 4.

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