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Q.

When 3.86 amperes current are passed through an electrolyte for 50 minutes, 2.4 grams of a divalent metal is deposited. The gram atomic weight of the metal (in grams) is

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a

24

b

12

c

64

d

40

answer is D.

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Detailed Solution

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Current (i) = 3.86 amp

t= 50 X 60 = 3000s

w= 2.4g

divalent metal (n) = 2

$w = \frac{E \times i \times t}{96500} = \frac{atomic weight \times i \times t}{n \times 96500}$

$Atomic weight = \frac{2.4 \times 2 \times 96500}{3.86 \times 3000} = 40 {gmol}^{- 1} .$

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