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When 4 gm graphite is burnt in limited supply of oxygen gas at 298K and 1 bar, 9 Kcal heat is released and no solid residue is left. The gaseous product formed is not absorbed in aqueous KOH solution. When 6gm graphite is burnt in excess of oxygen gas at 298 K and 1 bar, 48 Kcal heat is released and no solid residue is left. The enthalpy change of the following reaction at 298 K and 1 bar will be
$2 C O_{2} (g) \to 2 C O (g) + O_{2} (g)$

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+ 69 Kcal

+ 39 Kcal

+ 138 Kcal

+ 57 Kcal

answer is C.

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Detailed Solution

$\begin{array}{l} 2 C (s) + O_{2} \to 2 C O .... (1) Δ H_{1} = - 54 Kcal \\ 2 C (s) + 2 O_{2} \to 2 C O_{2} ... (2) Δ H_{2} = - 192 Kcal \end{array}$

$(1) - (2) \Rightarrow 2 C O_{2} \to 2 C O + O_{2}$

$Δ H = - 54 + 192 = 138 Kcal$

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