When 4 volt e.m.f is applied across a 1 farad capacitor, it will store energy of

We can simply solve this numerical problem by using the following process. (our goal is to calculate the energy stored in the capacitor)

Here, we will be using the following formula.

U = ½ × C × V²

Where,

• U = Energy stored in the capacitor
• C = Capacitance
• V = Voltage (or, E.M.F.)

By, putting the available data in the above mentioned formula, we get -

Energy stored in the capacitor = ½ × 1 × (4)² = 8 joules

(This will be considered as the final result.)

Hence, it will store 8 joules of energy.