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Q.

When 5 moles of $H e$ gas expand isothermally and reversibly at $300 K$ from 10 litre to 20 litre, the magnitude of the maximum work obtained is ___J. [nearest integer] $[g i v e n : R = 8.3 J K^{- 1} m o l^{- 1} a n d \log 2 = 0.3010]$

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answer is 8630.

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Detailed Solution

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$w = - 2.303 n R T \log \frac{V_{2}}{V_{1}} = - 2.303 \times 5 \times 8.3 \times 300 \log \frac{20}{10} = - 8630.37 J ≃ - 8630 J$

Magnitude of work = 8630J

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