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Q.

When 50l of air at STP (Standard Temperature and Pressure) is compressed isothermally to 10l, the amount and direction of heat exchange of air is [Use Patm=100kPa and ln(0.2)=1.61 ]

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a

8.05kJ flow out

b

8.05kJ flow in

c

5kJ flow out

d

5kJ flow in

answer is A.

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Detailed Solution

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Given, Initial volume of air at STP V1=50l=50×103m3 

Final Volume of air V2=10l=10×103m3 ; Patm=100kPa

Now, Process is Isothermally compressed.

∴ From 1st law of thermodynamics ΔQ=ΔU+Δ....(i),

Now, for Isothermal process 

ΔQ=ΔW

ΔW=50×0.001×100 ln(10/50)kJ

=5×ln(0.2)=5×1.61kJ

ΔQ=8.05kJ

Negative sign shows that heat rejected from the system ΔQ= 8.05kJ flows out

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When 50l of air at STP (Standard Temperature and Pressure) is compressed isothermally to 10l, the amount and direction of heat exchange of air is [Use Patm=100kPa and ln(0.2)=−1.61 ]