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When 6 identical cells of negligible internal resistance are connected in series in the secondary circuit of a potentiometer, the balancing length is ‘l’, balancing length becomes l/3 when some cells are connected wrongly, the number of cells connected wrongly are

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answer is B.

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Detailed Solution

$\frac{6 E}{ℓ} = \frac{(6 - 2 n) E}{1^{1}}$ Potential gradient is constant
$\frac{ℓ^{1}}{ℓ} = \frac{(6 - 2 n) E}{6 E}; \frac{ℓ}{3 ℓ} = \frac{6 - 2 n}{6}$
2 = 6 - 2n;2n = 4; n=2

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