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Q.

When 600 mL of 0.2 M HNO3 is mixed with 400 mL of 0.1MNaOH solution in a flask, the rise in temperature of the flask is _____×102  °C. (Enthalpy of neutralisation = 57 kJ mol1 and Specific heat of water = 4.2 JK1g1 ) (Neglect heat capacity of flask)

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answer is 54.

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Detailed Solution

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HNO3NaOH600mL×0.2M400mL×0.1M=120mmol=40mmol

HNO3+NaOHNaNO3+H2O

bef.12040aft800                       40mmol

ΔrH=40mmol×(57×103)Jmol=40×103mol×57×103Jmol=2280J

m  SΔT=2280

ΔT=22804.2×103=2280042×103=542.86×103

ΔT=54.286×102K, ΔT=54.286×1020C

ΔT=54.286

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