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When 9650 coulombs of electricity is passed through a solution of copper sulphate, the amount of copper deposited is
(given at. wt. of Cu = 63.6)

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0318g

3.18g

31.8g

63.6g

answer is B.

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Detailed Solution

$C u^{+ 2} + 2 e^{-} \to C u (s)$

$2 \times 96500 C$ 63.6g

9650 C will deposit $= \frac{63.6}{2 \times 96500} \times 9650 = 3.18 g$

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