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Q.

When a battery connected across a resistor of 16 Ω the voltage across the resistor is 12 V. When the same battery is connected across a resistor of 10 Ω voltage across it is 11V. The internal resistance of the battery in ohms is

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a

257

b

107

c

307

d

207

answer is B.

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Detailed Solution

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V = IR,E = V + Ir ; V1=I1R1⇒I1=V1R1=1216
V2=I2R2⇒I2=V2R2=1110
E = V1 + I1r = V2 + I2r
12+1216r=11+1110r ∴r=207 

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