When a block is placed on a wedge as shown in figure, the block starts sliding down and the wedge also start sliding on ground. All surfaces are rough. The centre of mass of $(w e d g e + b l o c k)$

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leftward and upward

only downward

leftward and downward

rightward and downward

answer is B.

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Detailed Solution

Net external horizontal on $w e d g e + b l o c k$ system is right ward ( $f r$ .), therefore, $C M$ will move right ward due to $m g$ on block it will move downward.

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