When a body is projected vertically up, at a point 'P' in its path, the ratio of potential to kinetic energies is 3 : 4. If the same body were to be projected with two times the initial velocity, the ratio of potential to kinetic energies at the same point is

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3 : 28

1 : 25

1 : 20

3 : 25

answer is A.

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Detailed Solution

if PE=3x and KE =4x then total energy is 7x

when velocity is double kinetic energy or total energy becomes 4 times i.e. 28x

potential energy remains 3x so kinetic energy becomes 28x-3x=25x

so ratio of potential to kinetic energy becomes $\frac{3 x}{25 x} = 3 : 25$

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