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When a body is thrown up vertically with initial velocity u

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Time of ascent = time of descent

$Time of flight = \frac{2 u}{g}$

Time of ascent is > time of descent

both A and B

answer is D.

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Detailed Solution

When a body is thrown up vertically

We get

1) Time of ascent = time of descent

$2) Time of ascent = time of descent = \frac{u}{g}$

$Time of flight T = \frac{2 u}{g}$

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