When a capillary tube is connected to a pressure head quantity of water flows per second is V (in c.c ). If another tube of same length but half the radius is connected to the first in series to the same pressure head, the quantity of water flowing through them per second will be ( in c.c)

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$\frac{V}{17}$

$\frac{V}{16}$

$\frac{17 V}{16}$

answer is B.

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Detailed Solution

$\begin{array}{l} Q = \frac{{πpr}^{4}}{8 ηl}; R_{s} = R_{1} + R_{2} \\ R_{s} = \frac{8 ηl}{{πr}^{4}} + \frac{8 ηl}{π {(\frac{r}{2})}^{4}} = 17 R \end{array}$

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