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When a car of mass 1200 kg is moving with a velocity of 15 $m s^{- 1}$ on a rough horizontal road, its engine is switched off. How far does the car travel before it comes to rest if the coefficient of kinetic friction between the road and tyres of the car is 0.5 ? (g=10 $m s^{- 2}$ )

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21.6m

25m

23.5m

22.5m

answer is D.

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Detailed Solution

a = μ g

From $v^{2} = u^{2} - 2 a s$
⇒ s = 225/10 = 22.5m

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