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When a cell is connected to an external resistance $2 Ω$ current through it is 2A. When the same cell is connected to an external resistance $1 Ω$ and current through it is 3A. Then the e.m.f of cell is

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6 V

4 V

2 V

8 V

answer is A.

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Detailed Solution

$i = \frac{E}{r + R} \Rightarrow r + R = \frac{E}{i}$

$\Rightarrow r + 2 = \frac{E}{2}$

$r + 1 = \frac{E}{3}$

$1 = E (\frac{1}{2} - \frac{1}{3})$

$E = 6 V$

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