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When a current flows through a conductor of cross section $10 c m^{2},$ the drift velocity of free electrons in it is $2 \times 10^{- 4} m s^{- 1} .$ It is stretched uniformly such that its area of cross-section is halved and same current is made to flow through it. Now the drift velocity is

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$4 \times 10^{- 4} m s^{- 1}$

$2 \times 10^{- 4} m s^{- 1}$

$5 \times 10^{- 5} m s^{- 1}$

$10^{- 4} m s^{- 1}$

answer is C.

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Detailed Solution

$I = n A e V_{d} \Rightarrow V_{d} \propto \frac{1}{A}$

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