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Q.

When a deuterium atom is bombarded onto ${}_{8}O^{16}$ nucleus an $α$ particle is emitted .Then the product nucleus is

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a

${}_{7}N^{14}$

b

${}_{4}B e_{^{}}^{9}$

c

${}_{5}B^{10}$

d

${}_{7}N^{13}$

answer is D.

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Detailed Solution

the reaction here it is

${}_{1}H^{2} + {}_{8}O^{16} = {}_{2}H e^{4} + {}_{7}N^{14}$ by conservation of proton and conservation of mass no.

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