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Q.

When a dielectric slab of thickness ‘t’ is inserted between the plates of a parallel plate capacitor its capacity increases. To bring back the capacitor to its original capacity, the distance between the plates is to be

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a

increased by $\frac{t}{K}$

b

decreased by $\frac{t}{K}$

c

increased by $t (1 - \frac{1}{K})$

answer is C.

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Detailed Solution

gap $= t [1 - \frac{1}{k}]$

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When a dielectric slab of thickness ‘t’ is inserted between the plates of a parallel plate capacitor its capacity increases. To bring back the capacitor to its original capacity, the distance between the plates is to be