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When a diode is forward biased, it has a voltage drop of $0.5 V$ . The safe limit of current through the diode is 10 $mA$ . If a battery of emf $1.5 V$ is used in the circuit, the value of minimum resistance (in $Ω$ ) to be connected in series with the diode so that the current does not exceed the safe limit is______________

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Detailed Solution

Voltage across resistance
$\begin{aligned} V_{R} = 1.5 - 0.5 = 1 volt \\ i R = 1 (= V_{R}) \\ ∴ R_{min} = \frac{1}{i} = \frac{1}{10^{- 2}} = 100 Ω \end{aligned}$

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