When a force (8i^+4j^) newton displaces a particle through (3i^-3j^) metre, the power is 0.6 W. The time of action of the force is

t=F→·S→P=(8i^+4j^).(3i^-3j^)10.6=120.6=20sec

When a force (8i^+4j^) newton displaces a particle through (3i^-3j^) metre, the power is 0.6 W. The time of action of the force is

t=F→·S→P=(8i^+4j^).(3i^-3j^)10.6=120.6=20sec

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When a force $(8 \hat{i} + 4 \hat{j})$ newton displaces a particle through $(3 \hat{i} - 3 \hat{j})$ metre, the power is 0.6 W. The time of action of the force is

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$t = \frac{\vec{F} \cdot \vec{S}}{P}$ = $(8 \hat{i} + 4 \hat{j})$ . $(3 \hat{i} - 3 \hat{j})$ $[\frac{1}{0.6}]$ = $\frac{12}{0.6} = 20 \sec$

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When a force (8i^+4j^) newton displaces a particle through (3i^-3j^) metre, the power is 0.6 W. The time of action of the force is

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When a force $(8 \hat{i} + 4 \hat{j})$ newton displaces a particle through $(3 \hat{i} - 3 \hat{j})$ metre, the power is 0.6 W. The time of action of the force is