When a force is applied on a wire of uniform cross - sectional area of 1 × 10–6 m2 and length 4m. The increase in length is 2mm. Energy stored in it will be (Y = 2 × 1011 N/m2)

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When a force is applied on a wire of uniform cross - sectional area of 1 × 10^–6 m² and length 4m. The increase in length is 2mm. Energy stored in it will be (Y = 2 × 10¹¹ N/m²)

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0.1 J

0.2 J

0.3 J

0. 4 J

answer is A.

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Detailed Solution

$e n e r e g y s t o r e d = \frac{1}{2} Y {(s t r a i n)}^{2} \times v o l u m e \frac{1}{2} \times 2 \times 10^{11} \times {(\frac{2 \times 10^{- 3}}{4})}^{2} \times 10^{- 6} \times 4 = 0.1 J$