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When a force $(8 i + 4 j)$ newton displaces a particle through $(3 i - 3 j)$ meter, the power is 0.6W. The time of action of the force is

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7.2 s

72 s

20 s

2 s

answer is A.

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Detailed Solution

$= (8 i + 4 j) = (3 i - 3 j)$

$P = 0.6 w$

$t = ?$

$P = \frac{work done}{time} = \frac{w}{t}$

$t = \frac{w}{P}$

$t = \frac{F S}{P}$

$= \frac{(8 i + 4 j) (3 i - 3 j)}{0.6}$

$= \frac{34 - 12}{0.6} = \frac{12}{0.6}$

$= \frac{12}{6} \times 10$

$t = 20 s$

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